a) x!x-2!=30, x pertence a N/x≥2
b)x+1!(x-1)=72, x pertence a N/x≥1
c)x!x-2!=5, x pertence a N/x≥2
Respostas
a)xx-1(x-2)(x-2)=30
x(x-1)=30
x²-x-30=0
∆=b²-4ac
∆=-1²-4(1).(-30)
∆=1+120=121
X’=-b± √∆
X’1+121=21+112=6
X’’=1-√1212=1-112=-5
b)x+1x(x-1)(x-1)=72
x²+x-72=0
∆=1²-4(1)(-72)
∆=1+278
∆=289
X’=-1±√2892
X’=-1+172
X=8
X’’=-1±√2892
X’’=-1-172
X=-9 S={(8)}
c) xx-1x-2!x-2!=5
x²-x-5=0
∆=b²-4ac
∆=(-1)²-4(1)(-5)
∆=21
X’=1±√212
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